Question

A car moves at the uniform speed of (216/5) km per hour. How much distance will it cover in (10/3) hours?​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Distance\:travelled=144\:km}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline{ \bold{Given:}}} \\ \tt: \implies Uniform \: speed = \frac{216}{5} \: km/h \\ \\ \tt: \implies time = \frac{10 }{3} \: hr\\ \\ \red{\underline{ \bold{To \: Find : }}} \\ \tt: \implies Distance \: travel =?$

• According to given question :

$\bold{Short \: method} \\ \tt: \implies Distance = Speed \times Time \\ \\ \tt: \implies Distance = \frac{216}{5} \times \frac{10}{3} \\ \\ \tt: \implies Distance =72 \times 2 \\ \\ \green{\tt: \implies Distance =144 \: km} \\ \\ \tt \circ \: Acceleration = 0 \: km/{h}^{2} \: \: \: \: (uniform \: speed) \\ \\ \tt \circ \: Speed = \frac{216}{5} \:km/h \\ \\ \tt \circ \: Time = \frac{10}{3} \: hr \\ \\ \bold{Alternate \: method : } \\ \tt: \implies s = ut + \frac{1}{2} {at}^{2 } \\ \\ \tt: \implies s = \frac{216}{5} \times \frac{10}{3} + \frac{1}{2} \times 0 \times (\frac{10}{3} )^{2} \\ \\ \tt: \implies s =72 \times 2 \\ \\ \green{\tt: \implies s =144 \: km}$