Question

a car moves for a speed of 50 kmph after 5sec it aquire speed of 70kmph find the distance covered

Answer 1

Hello,

Given that
Initial velocity = 50 km/hr = 50*5/18 m/sec
=250/18 m/sec

Final velocity = 70km/hr = 70*5/18 m/sec
=350/18 m/sec

Time taken = 5 seconds.

We know that
Acceleration = v-u/t
A =
$\frac{ \frac{350}{18} - \frac{250}{18} }{5} \\ \\ = \frac{ \frac{100}{18} }{5} \\ \\ = \frac{100}{5 \times 18} = \frac{20}{18} = \frac{10}{9} \: \: \frac{m}{ {sec}^{2} }$
Now,
S =ut +1/2 at²

Putting the values in the motion equation.

$s = \frac{250}{18} \times 5 + \frac{1}{2} \times \frac{10}{9} \times {5}^{2} \\ = \frac{1250}{18} + \frac{10}{18} \times 25 \\ \\ = \frac{1250 + 250}{18} = \frac{1500}{18} m$
So
The answer is
The distance travelled is equal to 83.3333333.....m
So ,
Taking the value approximately
Distance travelled = 1500/18 m or 83.33(approx)

Hope this will be helping you ✌️