A car moves for half of its time at 80km/ hr and for rest of time at40km/hr .If total distance covered is 60km/hr the average speed of the car is
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Answered by
1
given v1=80km/h, v2=40km/h, distance=60km
we know that
average speed=(v1+v2)/2
=(80+40)/2, =120/2, =60km/h
we know that
average speed=(v1+v2)/2
=(80+40)/2, =120/2, =60km/h
AmanA1:
coreect then is distance given just to misdirect as there is no need of it
Answered by
0
total distance =60 km
half.distance= 30km
1 st half-
distance=30km
speed - 80 km/h
t=d/s
=30/80
=3/8h
2nd half
d-30km
s=40km/h
t=d/s
=30/40
=3/4
total time = 3/8+3/4= 9/8= 1.125h
avg. speed = t.d./t.t.
=60/1.125
=53.3 km/h
half.distance= 30km
1 st half-
distance=30km
speed - 80 km/h
t=d/s
=30/80
=3/8h
2nd half
d-30km
s=40km/h
t=d/s
=30/40
=3/4
total time = 3/8+3/4= 9/8= 1.125h
avg. speed = t.d./t.t.
=60/1.125
=53.3 km/h
Sorry answer is wrong
if. correct pls mark d branliest....
aman is it correct
No the correct answer is 60
ok sorry
no dont be sorry you tried
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