Question

A car moves from stationary state with the acceleration of 5 m/s2. How much
distance would it cover in 15 s?
A
obiect is mori​

Answer 1

Answer:-

Given:

Initial Velocity of the car (u) = 0 m/s

[ since, the car has started from stationary position ]

Acceleration (a) = 5 m/s²

time (t) = 15 s

We know that,

v = u + at

[ where v is the final velocity ]

So,

⟶ v = 0 + (5)(15)

⟶ v = 75 m/s

Now,

Using second equation of motion ,

S = ut + 1/2 at²

So,

⟶ S = (0)(15) + 1/2 (5)(15)²

⟶ S = (0.5)(5)(15)(15)

⟶ S = 562.5 m

∴ The distance travelled by the car in 15 seconds is 562.5 m.

Answer 2

Answer:

✯ Given :-

• A car moves from stationary state with the acceleration of 5 m/s².

✯ To Find :-

• How much distance would be required to cover in 15 secs.

✯ Formula Used :-

❶ First equation of motion,

$\boxed{\bold{\large{v\: =\: u\: +\: at}}}$

❷ Second equation of motion,

$\boxed{\bold{\large{S\: = ut\: +\: \dfrac{1}{2}at²}}}$

✯ Solution :-

• Initial velocity (u) = 0 m/s
• Acceleration (a) = 5 m/s²
• Time (t) = 15 s

➣ According to the question by using the formula we get,

⓵ First equation of motion,

➙ v = u + at

⇒ v = 0 + (5)(15)

⇒ v = 0 + 75

⇒ v = 75 m/s

⓶ Second equation of motion,

➙ S = ut + $\dfrac{1}{2}$ at²

⇒ S = (0)(15) + $\dfrac{1}{2}$ × (5)(15)²

⇒ S = $\dfrac{1}{2}$ × 1125

➠ S = 562.5 m

$\therefore$ The distance travelled by a car in 15 secs is 562.5 m .

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