Question

A car moves in a circle at the constant speed
of 50 m/s and completes one revolution
in 40s. Determine the magnitude of
acceleration of car​

Answer 1

Answer:

The answer is 7.85m/s^2

Explanation:

We know that,

Distance = Speed x time  

So, d = 50 x 40 = 2000m  

D = 2 x 3.14 x r (circumference of the circle)

= 2000=2 x 3.14 x r

On calculating, r = 318.47 m

In this case, required acceleration will be centripetal acceleration.

So, a = (v x v)/r

A = (50x 50)/318.47

A = 7.85m/s^2

Thus the magnitude of acceleration is 7.85m/s^2.

Answer 2

Answer:

Explanation:

We know that, distance = speed*time

So, d = 50*40 = 2000m

d = 2*3.14*r (circumference of the circle)

=> 2000=2*3.14*r

On calculating, r = 318.47 m

In this case, required acceleration will be centripetal acceleration.

So, a = (v*v)/r

a = (50*50)/318.47

a = 7.85m/s^2

Hope this helps.