Question

A car moves in a circle at the constant speed of 50 m/s and complete one revolution in 40 s. Determine the magnitude of acceleration of the car​

Answer 1

We know that, distance = speed*time

So, d = 50*40 = 2000m

d = 2*3.14*r (circumference of the circle)

=> 2000=2*3.14*r

On calculating, r = 318.47 m

In this case, required acceleration will be centripetal acceleration.

So, a = (v*v)/r

a = (50*50)/318.47

a = 7.85m/s^2