Question

A car moves in a straight line from rest at t=0 and accelerates with 2m/s^2 slve the following table find velocity.displacement when time is given 2 sec

Answer 1

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Answer 2

Answer:

The velocity and displacement are 2 m/s and 4 m.

Explanation:

Given that,

Acceleration $a = 2\ m/s^2$

Time $t = 2\ sec$

The distance of the car is

Using equation of motion

$s = ut+\dfrac{1}{2}at^2$....(I)

Where, s = distance

u = initial velocity

a = acceleration

t = time

Put the value into the equation (I)

$s=0+\dfrac{1}{2}\times2\times2\times2$

$s= 4\ m$

The velocity is equal to the displacement divided by the time.

$v = \dfrac{d}{t}$

Where, d = displacement

t = time

v = velocity

Put the value of d and t into the formula

$v =\dfrac{4}{2}$

$v = 2\ m/s$

Hence, The velocity and displacement are 2 m/s and 4 m.