A car moves in a straight line from rest at t=0. It accelerates with 2m/s^2.
Displacement= 25m, find time and velocity.
Answers
Answer:
- Time = 5 secs
- Velocity = 10 m/s
Explanation:
Given that ;
Initial velocity (u) = 0
Acceleration (a) = 2 m/s²
Displacement(s) = 25 m
We will use equation of motion :
v² - u² = 2as
⇒ v² - 0 = 2 * 2 * 25
⇒ v² = 100
⇒ v² = (10)²
⇒ v = 10 m/s
Hence, the velocity of the car is 10 m/s.
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Again, using equation of motion ;
v = u + at
⇒ 10 = 0 + 2 * t
⇒ 10 = 2t
⇒ t =
⇒ t = 5 secs
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Hence, the time take by car is 5 secs and the velocity acquired is 10 m/s.
Solution :-
As provided :-
▪️Initial velocity = 0
▪️Acceleration = 2 m/s²
▪️Displacement = 25 m
Now we have got the Displacement , acceleration and the time.
So we can use the Motion equation :-
S = ut + 1/2 at²
→ 25 = 0(t) + 1/2 × 2 × t²
→ 25 = t²
→ t = ±5
But as time can never be negative
So the time taken = 5 sec
Now we have to find out the velocity .
We have got two methods for finding out Velocity .
1. v = u + at
2. v² = u² + 2aS
So by First Method :-
v = u + at
→ v = 0 + 2(5)
→ v = 10 m/s
By using second method :-
v² = u² + 2aS
→ v² = 0² + 2(2)(25)
→ v² = 0 + 100
→ v² = 100
→ v = ± 10
But as acceleration was positive
→ v = 10 m/s
So