Science, asked by unknown764, 8 months ago

A car moves in a straight line from rest at t=0.It accelerates with 2m/s*2.Solve in table ​

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Answered by abhi569
4

Answer:

Explanation:

It starts from rest. means, initially, it had no velocity.

  u = initial velocity = 0

          Using, v = u + at.

⇒ v = 0 + (2)(2)

⇒ v = 4 m/s

         Using, v^2 = u^2 + 2aS

⇒ 4^2 = 0^2 + 2(2)S

⇒ 4 m = S

            For 2nd box,

⇒ v = u + at

⇒ 10 = 0 + 2(t)

⇒ 5 = t  = time

  Using, v^2 = u^2 + 2aS

⇒ 10^2 = 0 + 2(2)S

⇒ 25 m = S

          For 3rd,

⇒  v^2 = u^2 + 2aS

⇒ v^2 = 2(2)(25)

⇒ v^2 = 100

⇒ v = 10 m/s

        Using v = u + at

⇒ 10 = 0 + 2(t)

⇒ 5 = t  = time

      For 4th,

⇒ v = u + at

⇒ v = 0 + 2(10 min)

⇒ v = 20 min m/s  = 20*60 m/s = 1200 m/s

  Using, v^2 = u^2 + 2aS

⇒ 1200^2 = 0 + 2(2)S

⇒ 720000 m = S

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