Question

a car moves in a straight line from rest at t=0 it accelerates with 2m/s 2 solve the following table​

Answer 1

Answer:

The velocity and displacement are 2 m/s and 4 m.

Explanation:

Given that,

Acceleration a = 2\ m/s^2a=2 m/s

2

Time t = 2\ sect=2 sec

The distance of the car is

Using equation of motion

s = ut+\dfrac{1}{2}at^2s=ut+

2

1

at

2

....(I)

Where, s = distance

u = initial velocity

a = acceleration

t = time

Put the value into the equation (I)

s=0+\dfrac{1}{2}\times2\times2\times2s=0+

2

1

×2×2×2

s= 4\ ms=4 m

The velocity is equal to the displacement divided by the time.

v = \dfrac{d}{t}v=

t

d

Where, d = displacement

t = time

v = velocity

Put the value of d and t into the formula

v =\dfrac{4}{2}v=

2

4

v = 2\ m/sv=2 m/s

Hence, The velocity and displacement are 2 m/s and 4 m.