Question

A car moves in a straight line such that a short time its velocity is define by v=(3t^2+2t)m/s. where t is in seconds.
Determine its position and acceleration when t=3s. when t=0, s=0

Answer 1

Step-by-step explanation:

Position is obtained by integrating velocity (v) with time (t).

Thus, position (S) = ∫ v dt = ∫ 3t² + 2t = t³ + t² + c

At t = 3 s, S = (3)³ + (3)² = 36 ft

Acceleration is obtained by taking derivative of velocity (v) with respect to time (t).

Thus, a = dv/dt = 6t + 2

At t = 3 s, a =20 ft/s²