Question

A car moves on a circular path of radius 5 m. At
one instant the speed of car is 5 m/s and it is
decreasing at a rate of 5 m/s2. The angle between
acceleration vector and velocity vector at me
instant is​

Answer 1

Answer:

The angle between  acceleration vector and velocity vector at me  instant is​ 135°

Explanation:

A car moves on a circular path of radius 5 m.

At  one instant the speed of car is 5 m/s and it is  decreasing at a rate of

5 m/s2

Assume that there is a circular path.  The car is moving through.

Now take V as the velocity axis where V = 5 m/s

and the acceleration a= 5 m/s ^2

The radius of the path is r= 5m

Now we know that if we draw a tangent it will make 90°

As the acceleration is decreasing then it will make an angle of 45°

Hence the angle between  acceleration vector and velocity vector at  instant is​ 45+90= 135°

Answer 2

Answer:

the answer is 3π/4

Explanation:

refer to the above attachment.