Question

a car moves on a circular path of radius 5m. At one instant the speed of car is 5m/s and it is decreasing at a rate of 5 m/s^2.The angle between acceleration vector and velocity vector at this instant is
1)pi/3
2)pi/6
3)pi/4
4)3pi/4
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Answer 1

Answer

Option 4 : 3π/4

Centripetal acceleration ac

$\tt{ {a}^{c} = \frac{ {v}^{2} }{r} = \frac{25}{5} } = 5m/s²$

the tangential acceleration is given as aT = 5m/s²

so the net acceleration will be

$\tt{ \sqrt[2]{ {5}^{2} + {5}^{2} } }$

At angle π/4 to the aT

so angle between this net acceleration and velocity vector will be

$\tt{\pi - \frac{\pi}{4} } = 3\pi/4$

Answer 2

Answer:

option 4 3π/4 .....................