Question

a car moves on a circular road of radius of 40 with a speed of 60 km per hour find the coefficient of friction between the road and tires of the car​

Answer 1

Answer:

The car can turn without skidding at 40 km/h, thus option (a) is wrong.

Since µ=0, so only force on the car by the road is the Normal force and no frictional force. So for speed less than 40 km/h it will slip down. Option (b) is correct.

As stated above only force by the road on the car is normal force (N)horizontal component of which (Nsinθ) produces a centripetal acceleration=rv2 . So Nsinθ=rmv2⟹N=rsinθmv2 Where θ is angle of banking. Thus option (c) is wrong.

As above,N=rsinθmv2 , so N is always greater than rmv2 because sinθ is always <1. Similarly Ncosθ=mg⟹N=cosθmg So N is always >mg because cosθ is always <1. Thus option (d) is correct.

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Explanation:

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