Question

a car moves on a circular track of radius 5m. At one instant the speed ​

Answer 1

Answer:

Centripetal acceleration a

c

=

r

v

2

=

5

25

=5m/s

2

the tangential acceleration is given as a

T

=5m/s

2

so the net acceleration will be

2

5

2

+5

2

at angle π/4 to the a

T

so angle between this net acceleration and velocity vector will be π−

4

π

=3π/4

Answer 2

At one instant the speed of car is 5m/s and it is decreasing at a rate of 5m/s2. The angle between acceleration vector and velocity vector at this instant is.