A car moves on a straight road for first half time with uniform speed of 20m/s and the next half time with uniform speed of 60m/s, calculate his average speed.
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Method 1- speed=distance/time
t1= S/2×20=S/40
t2=S/2×60=S/120
t=t1+t2
t=S/40+S/120=S/30
Average speed=speed/time=S/S/30=30m/sex.
Method 2- let distance covered in 1st half time x and distance covered in second half time is y so,
Average speed=2×x×y/x+y=2×20×60/20+60=2400/80= 30m/sec.
t1= S/2×20=S/40
t2=S/2×60=S/120
t=t1+t2
t=S/40+S/120=S/30
Average speed=speed/time=S/S/30=30m/sex.
Method 2- let distance covered in 1st half time x and distance covered in second half time is y so,
Average speed=2×x×y/x+y=2×20×60/20+60=2400/80= 30m/sec.
Rainaebad:
I didn't understand Ur answer. Please explain.
And my answer is 40m/s.
Use the second method it is easy question
The answer is 30m/sec only
It's confirm
To find average speed the formula used is (2×V1×V2)/V1+V2 now put the value and get the answer.
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3
Answer:
the total distance covered by the car race 40 metre per second
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