A car moves through 40km at a speed of 60km/hr and next 40km of a speed of 80km/hr is brought to rest in 5second. Calculate the retradation
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Initial velocity u = 30 km/h
Final velocity v = 0 km/h
Acceleration a = (v2 − u2)/(2S)
= (0 − 900)(1000/3600)2 /(2x8)
= − 900x5x5/(18x18x2x8) m/s2
= − 4.34 m/s2.
Same breaking force means same acceleration. Now we have to calculate S for u = 60 km/h.
S = (v2 − u2)/(2a)
= − 3600 x 5x5/(18x18x2x(−4.34)) m/s2
= 800.05 m
Final velocity v = 0 km/h
Acceleration a = (v2 − u2)/(2S)
= (0 − 900)(1000/3600)2 /(2x8)
= − 900x5x5/(18x18x2x8) m/s2
= − 4.34 m/s2.
Same breaking force means same acceleration. Now we have to calculate S for u = 60 km/h.
S = (v2 − u2)/(2a)
= − 3600 x 5x5/(18x18x2x(−4.34)) m/s2
= 800.05 m
7064732640:
Where 30km/hr come from
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