Math, asked by GARYLEARNER, 1 month ago

A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60km/h for the next 15 minute the total distance covered by the car is???​

Answers

Answered by Ruchi8644
84

here u need to calculate to distance by using formula..

hope it helps u

Attachments:
Answered by Anonymous
161

Given

A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60km/h for the next 15 minute.

To find

  • Total distance covered by car

Solution

\\\qquad\quad{\underline{\bf{\red{First\: condition}}}}\\

A car moves with a speed of 40 km/h for 15 minutes

\\\bullet\:\sf Speed\:of \: a \: car = 40km/h

\bullet\:\sf Time = 15 min\\

Note :

  • 1 hour = 60 min
  • Time = 15/60 = 1/4 hour

\\\qquad\quad{\blue{\boxed{\sf{\blue{Speed=\dfrac{Distance}{Time}}}}}}\\\\

\implies\sf Distance=Speed\times time \\\\

\implies\sf D_1 = 40 \times \dfrac{1}{4} \\\\

\implies\sf D_1 = 10km \\

\therefore{\underline{\boxed{\tt{Distance\:travelled\: i.e \: \bf 10km}}}}

\:____________________________________________

\\\qquad\quad{\underline{\bf{\red{Second\: condition}}}}\\

A car moves with a speed of 60km/h for the next 15 minute.

\\\bullet\:\sf Speed\:of \: a \: car = 60km/h

\bullet\:\sf Time = 15 min\\

Convert min into hour

\implies\sf Distance=Speed\times time \\\\

\implies\sf D_2 = 60 \times \dfrac{1}{4} \\\\

\implies\sf D_2 = 15km \\

\therefore{\underline{\boxed{\tt{Distance\:travelled\: i.e \: \bf 15km}}}}

\:____________________________________________

{\large\ast}\:{\underline{\bf{\purple{Total\:distance\: travelled}}}}\:{\large\ast}\\\\

\implies\sf D_1 + D_2 \\\\

\implies\sf 10 + 15 \\\\

\implies\sf 25km \\

\therefore{\underline{\boxed{\tt{Total \: distance\:travelled\: by \: a\: car =\bf 25km}}}}

\:____________________________________________

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