Question

A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60km/h for the next 15 minute the total distance covered by the car is???

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Answer 1

Answer:

Total Distance covered = 25km.

Step-by-step explanation:

Given: Car travels with a speed of 40km/hr for the first trip of 15 minutes.

and then it travels with a speed of 60km/hr for rest 15minutes.

We know that Distance covered is the product of Speed and Time.

Distance covered = Speed × Time

So, let's find the distance covered in the first trip of 15 minutes when the speed of the car was 40 km/hr.

1 hr = $\sf \dfrac{15}{60}$

$\sf Distance = 40 \times \dfrac{15}{60}$

$\bf Distance = 10km$

Now, let's find the distance covered in the second trip of 15 minutes where speed was 60km/hr.

$\sf Distance = 60 \times \dfrac{15}{60}$

$\bf Distance = 15km$

Total Distance Covered = 10 km + 15 km

=> 25km

Answer 2

Answer:

Given :-

• A car moves with a speed of 40 km/ h for 15 minutes and then with a speed of 60km/h for the next 15 minutes.

Find Out :-

• The total distance covered by the car.

Solution :-

In 1st condition :

• Speed s1 = 40 km/h
• Time t1 = 15 minutes = $\dfrac{15}{60}$ hrs

➻ Distance d1 = (s1 × t1)

➻ Distance d1 = $40 \times \dfrac{15}{60}$

➻ Distance d1 = $40 \times 0.25$

➭ Distance d1 = 10 km

In 2nd Condition :

• Speed s2 = 60 km/h
• Time t2 = 15 minutes = $\dfrac{15}{60}$ hrs

➻ Distance d2 = (s2 × t2)

➻ Distance d2 = $60 \times \dfrac{15}{60}$

➻ Distance d2 = $60 \times 0.25$

➭ Distance d2 = 15 km

➩ Total distance (d) = (d1 + d2)

➢ Total distance (d) = 10 km + 15 km

➦ Total distance (d) = 25 km

∴ Total distance covered by the car is 25 km.