Question

A car moves with a speed of 40 km/h for 5 minutes and then with a speed of 60 km/h for the next 5 minutes .What is the total distance covered by the car?​

Answer 1

Given:

Speed of car for first 5 min,v₁= 40 km/h

Speed of car for next 5 min,v₂= 60 km/h

To Find:

The total distance covered by the car

Solution:

We know that,

• $\pink{\underline{\boxed{\bf{Distance=Speed\times Time}}}}$

We can write,

$\longrightarrow\rm{5\ min=\dfrac{5}{60}=\dfrac{1}{12}\ h }$

━━━━━━━━━━━━━━━━━━━━━━━━━

Let the distance covered by car in first 5 min be d₁

So,

$\longrightarrow\rm{d_{1}=v_{1}\times\dfrac{1}{12}}$

$\longrightarrow\rm{d_{1}=40\times\dfrac{1}{12}}$

$\longrightarrow\rm{d_{1}=\dfrac{10}{3}\ km}$

Now, let the distance covered by car in next 5 min be d₂

So,

$\longrightarrow\rm{d_{2}=v_{2}\times\dfrac{1}{12}}$

$\longrightarrow\rm{d_{2}=60\times\dfrac{1}{12}}$

$\longrightarrow\rm{d_{2}=5\ km}$

Now, let the total distance covered by the car be D

So,

$\longrightarrow\rm{D=d_{1}+d_{2}}$

$\longrightarrow\rm{D=\dfrac{10}{3}+5}$

$\longrightarrow\rm{D=\dfrac{10+15}{3}}$

$\longrightarrow\rm{D=\dfrac{25}{3}\ km}$

Hence, the total distance covered by the car is 25/3 km.

Answer 2

$\huge{\pink{A}\blue{N}\purple{S}\orange{W}\red{E}\blue{R}}$

Given:

Speed of car for first 5 min,v₁= 40 km/h

Speed of car for next 5 min,v₂= 60 km/h

To Find:

The total distance covered by the car

Solution:

We know that,

$\textsf\pink{\underline{\boxed{\bf{Distance=Speed\times Time}}}}$

We can write,

$⟶5 \:min=\frac{5}{60} =\frac{1}{12} h$

━━━━━━━━━━━━━━━━━━━

Let the distance covered by car in first 5 min be d₁

So,

$⟶d _1 =v_1×\frac{1}{12}$

$\longrightarrow\rm{d_{1}=40\times\dfrac{1}{12}}$

$\longrightarrow\rm{d_{1}=\dfrac{10}{3}\ km}$

Now, let the distance covered by car in next 5 min be d₂

So,

$⟶d _2=v_2×\frac{1}{12}$

$\longrightarrow\rm{d_2=60\times\dfrac{1}{12}}$

$\longrightarrow\rm{d_2=5 km}$

Now, let the total distance covered by the car be D

So,

$\longrightarrow\rm{D=d_{1}+d_{2}}$

$\longrightarrow\rm{D=\dfrac{10}{3}+5}$

$\longrightarrow\rm{D=\dfrac{10+15}{3}}$

$\longrightarrow\rm{D=\dfrac{25}{3}\ km}$

Hence, the total distance covered by the car is 25/3 km.

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