Question

a car moves with a speed of 40km/h for 15 minutes and then with a speed of 60 km/h for the next 15 minutes . find the total distance covered by the car in these 30 minutes​

Answer 1

Answer: 25 km

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Answer 2

correct Question

A car moves with a speed of 40km/h for 15 minutes and then with a speed of 60 km/h for the next is minutes . the total distance covered by the car.

Answer

Given

Let the time taken by the car for the first part of the journey be $\sf{t_1}$=15 minutes.

Let the time taken by the car for the second part of the journey be $\sf{t_2}$=15 minutes.

Let the speed of the car for the first part of the journey be $\sf{V_1}$=40 km/h.

Let the speed of the car for the second part of the journey be $\sf{V_2}$=60 km/h.

To Find

Total distance covered by the car

Formula to be used

• Distance covered = speed × Total time taken
• 1h = 60 minutes

Solution

Let the distance covered by the car in the first part of the journey be $\sf{d_1}$Let the distance covered by the car in the second part of the journey be $\sf{d_2}$

$\sf{t_1}$=15 minutes, I.e. 15 minutes × $\sf\frac{1}{60} = \frac{1}{4}$h

$\sf{t_2}$=15 minutes, i.e. 15 minutes × $\sf \frac{1}{60} = \frac{1}{4}$h

∴$\sf{d_1}$=$\sf{V_1}$×$\sf{t_1}$=40 km/h×$\sf (\frac{1}{4} )h$=10km

∴$\sf{d_2}$=$\sf{V_2}$×$\sf{t_2}$=60 km/h ×$\sf (\frac{1}{4} )h$=15km

=Total distance covered by the car =$\sf{d_1}$+$\sf{d_2}$ i.e. 10 km +15 km=25 km

So, the answer is 25 km.