Question

A car moves with a speed of 40km/hr for 15mins and then with a speed of 60km/hr for 15mins.Find the total distance covered by the car is

Answer 1

$\underline{\textbf{Hey Mate Here Is your Answer ..}}$

$\underline{\textbf{Given That..}}$

A car moves with a speed of 40km/hr for 15mins and then with a speed of 60km/hr for 15mins, Now We Need

To Find The Total Distance ..

So Let's Move For Solution ..

$\underline{\textbf{Solution..}}$

Now To Find The Total Distance Covered By Car Follow The Simple Steps ...

$\underline{\bold{De fine \: The \: Required\: terms }}$

Now Let

$\textbf{Distance Travelled In First 15 min = D1}$

And Similarly

$\textbf{Distance Travelled In Next 15 min = D2 }$

$\mathbf{\therefore\:Total\: Distance\: Covered\: By \:Car \:D1 \:+ \:D2 }$

$\underline{\textbf{To Find D1 }}$

Therefore Now We Know That ...

$\boxed{\mathbf{Distance\:= Speed \:\times\: Time}}$

So Now Here

$\mathbf{Distance\: = \:D1 }$

$\mathbf{Speed \:= \:40km/h }$

$\mathbf{Time \:= \:15min\: \longrightarrow\: 1/4 hr}$

Therefore How By Putting This Value In Formula We Have

$\mathbf{D1\: = \: 40km/h \:\times \:1/4 hr }$

That Is ..

$\boxed{\mathbf{Distance\:(D1) \: = 10km}}$

$\underline{\textbf{To Find D2 }}$

So Now Here

$\mathbf{ Distance\: = \:D2}$

$\mathbf{Speed \:= \:60km/h }$

$\mathbf{Time \:= \:15min\: \longrightarrow\: 1/4 hr}$

Therefore By Putting This Value I. The Distance Formula We Have..

$\mathbf{D2 \:= \: 60km/h \: \times\: 1/4 hr }$

That Is

$\boxed{\mathbf{Distance (D2) = 15km}}$

$\underline{\textbf{ Add Both D1 And D2 To Find The Total Distance }}$

Now We kNow that

$\mathbf{Total \:Distance\: ( \:D\: ) \:= \:D1 \:+\: D2}$

Now From Above We Know That

$\textbf{D1 = 10km}$

$\textbf{D2 = 15km}$

Therefore

$\mathbf{Total\: Distance\: (\:D\:)\:=\: 10km\: + \: 15km}$

That Is

$\boxed{\mathbf{Total\: Distance \:= \: 25km}}$

$\underline{\textbf{Hence The Required Answer Is ...}}$

$\boxed{\boxed{\mathbf{Distance\: Covered \:= 25km}}}$

Answer 2

$\textbf{Answer :}$


$\textbf{According to question we have given}$

$\textbf{At first Speed of car (s) = 40 km/hr.}$

$\textbf{Time (t) = 15 min.}$

= $\frac{15}{60}$

= $\frac{1}{4}$ in hr.

$\textbf{Distance (d) = ?}$

$Speed$ = $\frac{Distance}{Time}$

= $Distance$ = $Speed$ × $Time$

= $40$ × $\frac{1}{4}$

= $10\:km$ .......(1)


$\textbf{Also we have given that}$

$\textbf{Speed of car = 60 km/hr.}$

$\textbf{Time = 15 min.}$

= $\frac{1}{4}$ hr.

$Distance$ = $Speed$ × $Time$

= $60$ × $\frac{1}{4}$

= $15\:km$ .......(2)


$\underline\textbf{We\:have\:to\:find\:total\: Distance}$

So,

$\textbf{Total Distance covered by car = (1) + (2)}$

= $10\:+\:15$


= $\huge\textbf{25 km}$

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