Question

A car moves with a speed of 50 km/hr for 15min, and then with speed of 80 km/hr for the next 20 minutes Calculate the total distance covered by the car​

Answer 1

$s1 = 50km {h}^{ - 1} = \frac{50 \times 1000}{3600} m {s}^{ - 1}$

$t1 = 15 \: min = 15 \times 60 \: s$

$s2 = 80 \:km {h}^{ - 1} = \frac{80 \times 1000}{3600} m {s}^{ - 1}$

$t2 = 20 \: min = 20 \times 60 \: s$

$d1 = s1 \times t1$

$d1 = \frac{50 \times 1000}{3600} \times 15 \times 60 \: m$

$d1 = 12500 \: m$

$d2 = \frac{80 \times 1000}{3600} \times 20 \times 60 \: m$

$d2 = 26666.67 \: m$

$total \: distance \: = d1 + d2$

$total \: distance = 39166.67 \: m$