Question

A car moves with a velocity of 12m/s stops after 10s on applying brake.
a) Find the acceleration produced after applying brake
b) Calculate the distance it travels during this time​

Answer 1

Answer:

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Explanation:

 final velocity (V) = 0 ( as it stops after applying brakes)

    initial velocity ( U) =12m/s

     time (T) = 10s

a) acceleration(A) produced after braking

    V= U+AT

     0 = 12+ A*10

    A = -1.2m/s^2 ( as the car is decelerating)

b) distance(S) it travels during the time

     v^2-U^2 = 2AS

       0 - 144 = 2(-1.2)S

          -144/ -2.4 = s

             S = 60m