A car moves with a velocity of 12m/s stops after 10s on applying brake. a) Find the acceleration produced after applying brake b) Calculate the distance it travels during this time.
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Answer:
a) -6/5 or -1.2 m/s^2
b) 60m
Explanation:
Initial velocity (u) = 12m/s
Final velocity (v) = 0m/s
[Because car stops at last]
Time (t) = 10s
a) V = U + AT ( Formula )
=> 0 = 12 + A × 10
=> A × 10 = -12
=> A = -12/10 = -6/5 m/s^2
( -ve sign shows that acceleration acts on the opposite side of the motion of car because it decreases the speed )
b) V^2 - U^2 = 2 A S ( Formula )
=> (0)^2 - (12)^2 = 2 (-1.2) × S
=> 0 - 144 = -2.4S
=> S = -144/-2.4 = 60m
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