Physics, asked by gloryng2018, 11 months ago

A car moves with a velocity of 72km/hr it is brought to rest in 10seconds find A,the velocity in m/s B,the retardation

Answers

Answered by Anonymous
1

Answer:

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Explanation:

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Answered by vladimirputin
0

Answer:

Explanation:

initial velocity(u) = 72 km/hr =72 * 5/18 = 20 m/s

time(t) is 10 seconds

final velocity(v)=0 m/s as the particle comes to rest

applying equation of motion

v=u+at

0=20+a(10)

by solving this we get

a = -2m/s^2, (i.e. retardation is 2m/s^2)

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