A car moves with a velocity of 72km/hr it is brought to rest in 10seconds find A,the velocity in m/s B,the retardation
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Explanation:
initial velocity(u) = 72 km/hr =72 * 5/18 = 20 m/s
time(t) is 10 seconds
final velocity(v)=0 m/s as the particle comes to rest
applying equation of motion
v=u+at
0=20+a(10)
by solving this we get
a = -2m/s^2, (i.e. retardation is 2m/s^2)
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