Question

A car moves with an initial velocity 30m/s then stops after 10 sec. Find the retardation​

Answer 1

Question:-

A car moves with an initial velocity 30m/s then stops after 10 sec. Find the retardation

Answer:-

• The retardation is 3 m/s²

To find:-

• The retardation

Solution:-

• Initial velocity = 30 m/s
• Final velocity = 0 m/s
• Time taken = 10 s

We have to find the retardation (negative acceleration)

$\boxed{ \mathfrak{ \large{acceleration = \frac{v - u}{t} }}}$

Where,

• v = final velocity
• u = Initial velocity
• t = time taken

According to question,

$\large{ \tt : \implies \: \: \: \: acceleration = \frac{0 - 30}{10} }$

$\large{ \tt : \implies \: \: \: \: acceleration = \frac{ - 30}{10} }$

$\large{ \tt : \implies \: \: \: \: acceleration = - 3 \: {ms}^{ - 2} }$

Hence,

The retardation is 3 m/s²

Answer 2

☆ Solution ☆

Given :-

• Initial velocity ( u) = 30m/s
• Final velocity ( v ) = 0 m/s
• Time ( t) = 10 sec

To Find :-

• The retardation

Step-by-Step-Explaination :-

Here, we use Newton first law

=> V = U + AT

=> 0 = 30 + a × 10

=> - 30 = 10a

=> - 30 ÷ 10 = a

=> - 3 = a

Hence,

• The retardation of car = - 3 m/s²