Question

A car moves with an initial velocity 30m/s then stops after 10 sec. Find the retardation *​

Answer 1

Given :

• Initial velocity, u = 30 m/s

• Final velocity, v = 0 m/s (as it stops)

• Time, t = 10 seconds

To find :

• Retardation, a [Negative acceleration]

According to the question,

By using Newtons first equation of motion,

➞ v = u + at

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

➞ 0 = 30 + a × 10

➞ 0 - 30 = 10a

➞ - 30 = 10a

➞ - 30 ÷ 10 = a

➞ - 3 = a

So, the retardation of the car is 3 m/s²

___________________

_______________________

More formulas :

Newton's first equation of motion :

• v = u + at

Newton's second equation of motion :

• s = ut + ½ at²

Newton's third equation of motion :

• v² = u² + 2as

Answer 2

Answer:

Provided information :-

• Initial velocity(u) = 30 m/s
• Time taken (T) = 10 Sec
• Final velocity (V) = 0 m/s (as it stops)

What to do :-

Find the retardation (A)

Let's solve :-

Here, we will use newton first Equation

➸ V = U + AT

➸ 0 = 30 + a × 10

➸ 0 - 30 + 10a

➸ -30 = 10a

➸ -30 ÷ 10 = a

➸ -3 = a

✭ Retardation = 3 m/s ✭