Question

a car moves with initial velocity 2 metre per second and uniform acceleration 3 metre per second square. calculate the velocity when it has travelled a distance of 77 m.

Answer 1

solution

initial velocity, u= 2m/s

acceleration, a= 3m/s^2

Distance travelled, d= 77m

using appropriate formula → v^2 - u^2 = 2as

=> v^2 - 2^2 = 2.3.77

=> v^2 - 4 = 462

=> v^2 = 466

=> v = 21.5 m/s

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hope it help...☺

Answer 2

given
$u = 2 \frac{m}{s} \\ a = 3 \frac{m}{ {s}^{2} }$
Calculating final velocity by 3rd equation of motion
${v}^{2} - {u}^{2} = 2as \\ {v}^{2} = 4+ 2 \times 3 \times 77 \\ {v}^{2} =4+ 462 \\ v = \sqrt{466}$