Question

A car moves with speed 60 km/h for 1 hour in east direction
and with same speed for 30 min in south direction. The
displacement of car from initial position is
​

Answer 1

Answer:

Mmmm

Explanation:

Thinking.............

Speedv=60km/h

Time

t

1

=1h

t

2

=30min

Now, distance travelled by a car in East direction

D

1

=v×t

1

D

1

=60×1

D

1

=60km

Now, distance travelled by a car in south direction

D

2

=v×t

2

D

2

=60×

2

1

D

2

=30km

Now, the displacement from intial

osition

D=

(D

1

)

2

+(D

2

)

2

D=

(60)

2

+(30)

2

D=

3600+900

D=

4500

D=30

5

Hence, the displacement of car from initial position is 30

5

m

Answer 2

Answer:

Given that,

Speedv=60km/h

Time

  t1=1h

 t2=30min

Now, distance travelled by a car in East direction

  D1=v×t1

 D1=60×1

 D1=60km

Now, distance travelled by a car in south direction

  D2=v×t2

 D2=60×21

 D2=30km

Now, the displacement from intial position

  D=(D1)2+(D2)2

 D=(60)2+(30)2

 D=3600+900

 D=4500

 D=305

Hence, the displacement of car from initial position is 305