Question

A car moves with speed of 60 km/h for 1 hour in east direction and then with same speed

for 30 min in south direction. Find his distance and direction. pls answer me fast​

Answer 1

Answer:

Given that,

Speedv=60km/h

Time

t

1

=1h

t

2

=30min

Now, distance travelled by a car in East direction

D

1

=v×t

1

D

1

=60×1

D

1

=60km

Now, distance travelled by a car in south direction

D

2

=v×t

2

D

2

=60×

2

1

D

2

=30km

Now, the displacement from intial position

D=

(D

1

)

2

+(D

2

)

2

D=

(60)

2

+(30)

2

D=

3600+900

D=

4500

D=30

5

Hence, the displacement of car from initial position is 30

5

m

Step-by-step explanation:

pleas

Answer 2

Given:

speed = 60km/hr

Time (t1)= 1hr , time(t2)=30min= 30/60= 1/2 hr

Distance travelled by a car in East direction(s1)= speed× t1 = 60× 1= 60km

Distance travelled by a car in south direction(s2)= speed× t1 = 60×1/2= 30 km

Displacement from intial position(s)= √(s1)²+(s²)²= √ (60)²+(30)²

= √3600+900

= √900(4+1)

= 30√5

Displacement= 30√5km

_____________________________

The displacement of car from initial position is 30√5km

_____________________________

Hope this will help you...