Question

A car moves with speed of 60 km/have for 1 hour in East direction and with same speed for 30 min in south direction the displacement of car from initial position is

Answer 1

30 min = 0.5 hour

Displacement along East = Velocity × Time
= 60kmph × 1h
= 60 km

Displacement along South = Velocity × Time
= 60kmph × 0.5h
= 30 km

Total Displacement = sqrt(60^2 + 30^2) ……[∵ Both are perpendicular]
= 67.08 km

Displacement of car from initial position is 67.08 km

Answer 2

hope it helps you............