Question

A car moves with the speed of 80km/hr for 15 mins and then 100km/hr for another 15 mins . What is the total distance covered by the car.

Answer 1

Answer:

45 km is the total distance covered.

Answer 2

$\LARGE\bold{ \red{ \boxed{\blue{\underline{\mathtt{\red{Given:↓}}}}}}}$

• A car moves with the speed of 80km/hr for 15 mins
• And then 100km/hr for another 15 mins.

$\LARGE\bold{ \orange{ \boxed{\blue{\underline{\mathtt{\orange{Find:↓}}}}}}}$

• The total distance covered by the car.

$\LARGE\bold{ \green{ \boxed{\blue{\underline{\mathtt{\green{Solution:↓}}}}}}}$

In the 1st case:-

$\large \bold{ \displaystyle{The \: speed \: of \: the \: car=}{ \large \bold\pink{ \boxed{80 \: kmph}}}}$

$\large \bold {\displaystyle {Total \: time \: for \: which \: the \: car's }} \\ \large \bold { \displaystyle {speed \: was \: 80 \: kmph = { \large \bold \pink{ \boxed{15 \: min}}}}}$

$\large \bold{ \displaystyle{\therefore The \: distance \: covered \: in \: 15 \: min = }}$

$\large \bold \red{ \displaystyle{Speed = \frac{ Distance}{Time}}}$

$\LARGE\bold{ \blue{ \boxed{\blue{\underline{\mathtt{\blue{Note:↓}}}}}}}$

• Here the speed is in Kilometers per Hour, So we will divide total minutes in an hour by the time traveled by the car in 80 kmph.

So,

$\: \: \: \: \: \: \: \large \bold{60 \div 15 = \large \bold \pink{ \boxed {4}}}$

$\implies\large \bold { \displaystyle{(80 \div 4)km \implies \Large \bold \green {\boxed{20 \: km}}}}$

So, in Case 1 the car travelled:

$\implies \Large \bold \green {\boxed{20 \: km}}$

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In 2nd Case:-

$\large \bold{ \displaystyle{The \: speed \: of \: the \: car=}{ \large \bold\pink{ \boxed{100 \: kmph}}}}$

$\large \bold {\displaystyle {Total \: time \: for \: which \: the \: car's }} \\ \large \bold { \displaystyle {speed \: was \: 80 \: kmph = { \large \bold \pink{ \boxed{15 \: min}}}}}$

$\large \bold \red{ \displaystyle{Speed = \frac{ Distance}{Time}}}$

(Same Note given above⬆️)

So,

$\: \: \: \: \: \: \: \large \bold{60 \div 15 = \large \bold \pink{ \boxed {4}}}$

$\implies\large \bold { \displaystyle{(100 \div 4)km \implies \Large \bold \orange {\boxed{25 \: km}}}}$

So, in Case 1 the car travelled:

$\implies \Large \bold \orange {\boxed{25 \: km}}$

So, the total distance covered by the car

$\implies\large\bold{\displaystyle{20 km + 25 km}}$

$\implies \Large \bold \red{\boxed{45 \: km}}$

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So,

$\LARGE\bold{ \orange{ \boxed{\blue{\underline{\mathtt{\orange{Your \:Answer:↓}}}}}}}$

$\implies \Large \bold \purple{\boxed{45 \: km}}$

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Hope it helps.