Question

a car moves with uniform velocity 36kmh-1 for 10 minutes now its velocity becomes 72kmh-1. Find the distance covered by car.​

Answer 1

Answer:

150m

Explanation:

First find accelaration i.e. 1m/s

Then calculate distance using ut+1/2at^2

Distance will be 150m

Answer 2

Answer:

u = 36kmph = 36×5/18 =10 m/s

time, = 10 mins = 10×60 = 600 s

v = 72kmph = 72×5/18 = 20m/s

acceleration = v - u / t

= 20 -10 / 600 = 10/600 = 1/60 m/s²

According to laws of equations of motion,

v² = u²+ 2as

20² = 10² +2 (1/60)s

400= 100 + (1/30)s

1/30 s = 300

s/30 = 300

s = 9000m = 9km