Question

A car moves with velocity 10m/s towards east in 5seconds its velocity changes to 10m/s towards north.then change in velocity of car is​

Answer 1

Answer:

Change in the velocity of the car = 10√2 m/s

Explanation:

If the East direction is along x-axis and the North direction is along y-axis then

Initial Velocity of the car = $10\hat i$

Final velocity of the car = $10\hat j$

Change in velocity

= Final Velocity - Initial Velocity

= $10\hat i-10\hat j$

= $10(\hat i-\hat j)$

Magnitude of the velocity = 10√2 m/s

Direction of the velocity = 135° from the East diretcion

Hope this helps.