Question

a car moving 30 m /s on acircular path of radius 500 mits speed is incresing at the rate of 2 m/s2 the accelaration of car is??

Answer 1

Tangential acc(a) = 2m/s²
Centripetal acc(a')= v²/r = 30²/500 = 9/5
Now , net acc = √(a²+a'²) = √(4 + 81/25) = √(181/25) = √181 / 5 m/s²