A car moving along a straight highway with a speed of 126km/hr is brought to stop within a distance of 200m what is retardation? and time taken to come to rest
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1
-u^2 = 2ax and 126 km/hr = 35 m/s
=> a = - 35^2/(2*200) = -3.0625 m/s^2
0 = 126 -3.0625*t
=> t = 41.14s
=> a = - 35^2/(2*200) = -3.0625 m/s^2
0 = 126 -3.0625*t
=> t = 41.14s
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Answered by
2
a=49/16 m/s^2
t=560/49 second
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