A car moving along a straight highway with speed of 126 km h^-1 is brought to a stop within a distance of 200 m.Calculate the retardation of the car
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Answer:
time taken =distance /speed
t=200/126×5/18
t=200/35
a=(v-u)/t
a=(0-35)200/35
a=-200m/sec.^2
retardation=200m/sec.^2
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