A car moving along a straight highway with speed of 126 km h-1 is brought to a stop within a distance of 200m . what is the retardation of the car (assumed uniform).and how long does it take for the car to stop ?
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Explanation:
Given,
Velocity of car v=126 km/h=35 m/s
Displacement s=200 m
Final velocity v=0 m/s
Apply second kinematic equation to calculate retardation a
v
2
−u
2
=2as
⇒a=
2s
v
2
−u
2
=
2×200
0−35
2
=−3.0625 m/s
2
Apply first kinematic equation to calculate time t
v=u+at
⇒t=
a
v−u
=
3.0625
0−35
=11.43 sec
Hence, retardation is 3.06 m/s
2
and time take to stop is 11.4 sec
hope its help u
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