A car moving along a straight highway with speed of 126 km/ h to brought to stop within a distance of 200 m. what is the retardation of the car and how long does it take for the car to stop? subject:
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Answered by
1
u=126km/h initial velocity
v=0
s=0.2km
a=?
now use formula v^2-u^2=2as
0-15786=2a(0.2)
a=39690km/h^2
change unit according to asked.
v=0
s=0.2km
a=?
now use formula v^2-u^2=2as
0-15786=2a(0.2)
a=39690km/h^2
change unit according to asked.
Answered by
2
given that u=126km/h
v=0
s=0.2km
so 2as=v^2-u^2
a=v^2-u^2/2s
a=39690
v=0
s=0.2km
so 2as=v^2-u^2
a=v^2-u^2/2s
a=39690
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