a car moving along a straight highway WITH speed of 35 M/S is brought to a stop within a distance of 200M.how long does it take for the car to stop?
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Answered by
15
Answer:40/7 seconds
Explanation:
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Answered by
15
Answer:
Explanation:
Since the car is brought to stop hence it's final velocity will be zero. It's initial velocity will be 35m/s
Now, from acceleration we have change in velocity divided by time interval
Which is
A= v-u/the
We have v= u+at
Another equation we have as
v²-u²= 2as
Here distance given is 200m
35²= 400a
a=35²/400
= 3.0625
Putting value in
v=u+ at
35= 3.0625*t
t=6.125
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