A car moving along a straight highway with speed of 35 ms is brought to a st
within a distance of 200m. How long does it take for the car to stop? V-35
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Answer:
11.43 seconds
Explanation:
Let the time taken to stop the car be "t"
Acceleration of car = Change in velocity / Time
= (0 m/s - 35 m/s) / t
= -35/t
From equation of motion
- S = ut + 0.5at²
200 = 35t + (0.5 × -35/t × t²)
200 = 35t - 17.5t
200 = 17.5t
t = 200/17.5 s
t ≈ 11.43 s
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