A car moving along a straight highway with speed of 54 km/h is brought to stop within a distance of 50m. How long does the car take to stop?
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Answer: u = 54 km/h =54000/3600 = 540 /36 = 15m/s
using
v^2 - u^2= 2as we have
0 - 225 = 2 a (50)
-225 = 100a
a= -2.25
now, v= u+at
0 = 15 + (-2.25)t
t= 15/2.25 = 6.67s
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