A car moving along a straight highway with speed of 72 km/h-1 is brought to a stop within distance 100 m.what is retardation of the car nd how long it take for car to stop solve it
Answers
Answered by
300
u =72 km /h
= 20 m/s
v=0
s =100m
v^2-u^2= 2as
-u^2= 2×a×100(v=0)
- 20^2=200a
-400=200a
a=-2 m/s^2
= 20 m/s
v=0
s =100m
v^2-u^2= 2as
-u^2= 2×a×100(v=0)
- 20^2=200a
-400=200a
a=-2 m/s^2
Answered by
101
If a car moving along a straight highway with speed of 72 km/h-1 is brought to a stop within distance 100 m as well as the retardation of the car will be
U =72 km /h= 20 m/s v=0,
s =100m,
v^2-u^2= 2as -u^2= 2×a×100(v=0) - 20^2=200a -400=200a a=-2 m/s^2.
Similar questions