Question

a car moving along a straight line at a speed of 72 km/hr stops in 5s afer the brakes are applied find its acceleration and plot the graph of speed versus time and using the graph find the distance covered by the car after the brakes are applied.

Answer 1

Answer:

4m/sec^2 is the acveleration

Explanation:

we know v = u+at

here finally car comes to resy. Hence final velocity 'v' =0

Initial velocity 'u' =72km/hr

u = 72*5/18 m/sec =20 m/sec

time t = 5sec

since breaks are applied in the opposite direction of motion of car acceleration 'a' will be negative.

v=u+at

0=20-a5

20 = 5a =>a= 4m/sec^2 is ur answer. Hope it helps u

Answer 2

Answer:

4m/s²

Explanation:

May It helps you