Question

a car moving along a straight line covers 40m in 5 second and next 60 meter 7 seconds . the average speed of a car is​

Answer 1

Question:-

a car moving along a straight line covers 40m in 5 second and next 60 meter 7 seconds . the average speed of a car is?

Answer:-

$\large\sf{ \leadsto 8.3333 \ ms^{-1}}$

Given that:-

distance in first interval : 40m

time in first interval: 5 seconds

distance in second interval: 60m

time in second interval: 7 seconds

Formula used:-

$\large\rm{ Average \ speed = \frac{total \ distance}{total \ time}}$

Solution:-

➟ $\large\rm{ Average \ speed = \frac{total \ distance}{total \ time}}$

➟ $\large\sf { \frac{40+60}{5+7}}$

➟ $\large\sf { \frac{100}{12}}$

➟ $\large\sf { \cancel\dfrac{100}{12}}$

➟ $\large\boxed{\sf{ \therefore 8.3333 \ ms^{-1}}}$ is the required answer

Answer 2

Answer:

Solution:-

➟ { Average \ speed = \frac{total \ distance}{total \ time}}Average speed=

total time

total distance

➟ \frac{40+60}{5+7}}

5+7

40+60

➟ {100}{12}}

12

100

➟ \100}{12}}

12

100

➟ \therefore 8.3333 \ ms^{-1}}}

∴8.3333 ms

−1

is the required answer