A car moving along a straight road
at speed of 36 m/s comes to rest after
travelling qom. Assuming the retardation to
be uniform and find it value what time
does it take to cover the distance
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Answer:
Initial velocity (v) = 36 m/s Final velocity (u)= 0 Distance travelled (s)= 90m We have, v² - u²= 2as ⇒ a= v² - u²/2s a = 0 - 36²/2(90) = -1296/180= -7.2m/s² Also, v = u+at t = v-u/a = 0-36/ -7.2 = 5 secs Thus, acceleration is -7.2m/s² and time taken to travel that distance is 5 secs.
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