A car moving along a straight road with a velocity of 27 kmph is brought to rest within a distance of
50 m. Find the retardation of the car and time taken to brought it to rest (assume retardation is uniform).
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Answer:
u=126 km/h=126×
18
5
m/s=35m/s
v=0
s=200m
Newton's Equation of motion
v
2
−u
2
=2as
0
2
−35
2
=2a(200)
a=−3.0625m/s
2
Also
v=u+at
0=35−3.06t
t=11.4s
Explanation:
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