a car moving along highway with a speed of 50m/s brought to stop with the distance of 400m . what is the retardation pf the car and how long does it take for the car to stop
Answers
Answered by
1
Answer:
Given :-
U = 50 m/s
S = 400 m
APPLIED FORMULA :-
V² - u² = 2as
CALCULATION :-
0² - 50² = 2× a × 400
50× 50 = 2× a × 400
a = 3.25 m/s² (Ans)
⚕️ßàúryæ⚕️
Similar questions