Question

a car moving along highway with a speed of 50m/s brought to stop with the distance of 400m . what is the retardation pf the car and how long does it take for the car to stop​

Answer 1

Answer:

Given :-

U = 50 m/s

S = 400 m

APPLIED FORMULA :-

V² - u² = 2as

CALCULATION :-

0² - 50² = 2× a × 400

50× 50 = 2× a × 400

a = 3.25 m/s² (Ans)

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