Question

a car moving at 12 metre per second due east attains a speed 16 metre per second towards north in 4 seconds The magnitude of its average acceleration in metre per second square is​

Answer 1

a=v/t

so, a1= 12/4 m/s2= 3 m/s2

... a2=16/4 m/s2=4m/s2

so by vector adding,resultant accileration is,a'=

$\sqrt{ {4 }^{2} + {3}^{2} + 2 \times 4 \times 3 \cos(90 ) } = 5$

therefore, average acceleration, a"= 5/4 m/s2= 1.25 m/s2